This reminds me of a math joke I made up several years ago.
Fermat's Last Theorem. There exist no triplets of positive integers x, y and z such that x^n + y^n = z^n for n>2.
Proof. Assume there are such x,y,z > 0. Multiply both sides of the equation by ρ^n, where ρ>0 (supposed to be the Greek letter rho), giving (xρ)^n + (yρ)^n = (zρ)^n. By pronunciation, zρ = 0 = (zρ)^n. This is a contradiction, since the LHS > 0. Never mind that this also proves that there are also no right triangles with integer side lengths (in the US, at least).
5 comments:
0y (0 is a zero) is an abbreviation for "naughty."
This reminds me of a math joke I made up several years ago.
Fermat's Last Theorem.
There exist no triplets of positive integers x, y and z such that
x^n + y^n = z^n for n>2.
Proof.
Assume there are such x,y,z > 0. Multiply both sides of the equation by ρ^n, where ρ>0 (supposed to be the Greek letter rho), giving
(xρ)^n + (yρ)^n = (zρ)^n.
By pronunciation, zρ = 0 = (zρ)^n. This is a contradiction, since the LHS > 0.
Never mind that this also proves that there are also no right triangles with integer side lengths (in the US, at least).
Can you tell I'm procrastinating?
Brofo,
Considering your entire (regular) audience is British, the joke falls rather flatly on its bum.
It must've hurt having to find the rho symbol.
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≤≥÷…¬˚π“ºª•¶§£¢é
I'm put in mind of GIS 'procrasti nate', a particularly travolting example of Splantrik's Superness.
I Putin the rho character by Google-searching for it, and then simply copying the character which appeared in several of the hits.
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